How Much Iron Can Be Extracted from 25.0g of Fe2O3- A Comprehensive Analysis

How much iron can be recovered from 25.0g of Fe2O3? This is a question that often arises in the field of metallurgy and material science. Iron oxide, or Fe2O3, is a common ore used to extract iron, and the process of recovery is of great interest to researchers and industrialists alike. In this article, we will explore the calculation involved in determining the amount of iron that can be extracted from a given mass of Fe2O3.

The first step in understanding how much iron can be recovered from Fe2O3 is to determine the molar mass of the compound. Fe2O3 consists of two iron atoms and three oxygen atoms. The atomic mass of iron (Fe) is approximately 55.85 g/mol, while the atomic mass of oxygen (O) is approximately 16.00 g/mol. Therefore, the molar mass of Fe2O3 can be calculated as follows:

Molar mass of Fe2O3 = (2 × atomic mass of Fe) + (3 × atomic mass of O)
Molar mass of Fe2O3 = (2 × 55.85 g/mol) + (3 × 16.00 g/mol)
Molar mass of Fe2O3 = 111.70 g/mol + 48.00 g/mol
Molar mass of Fe2O3 = 159.70 g/mol

Now that we have the molar mass of Fe2O3, we can determine the amount of iron in 25.0g of the compound. The molar ratio of iron to Fe2O3 is 2:1, meaning that for every mole of Fe2O3, there are two moles of iron. To calculate the amount of iron in 25.0g of Fe2O3, we can use the following formula:

Amount of iron (g) = (mass of Fe2O3 × molar ratio of iron to Fe2O3) / molar mass of Fe2O3

Amount of iron (g) = (25.0g × 2) / 159.70 g/mol
Amount of iron (g) = 50.0g / 159.70 g/mol
Amount of iron (g) ≈ 0.313 g

Therefore, approximately 0.313 grams of iron can be recovered from 25.0g of Fe2O3. This calculation provides a fundamental understanding of the iron recovery process and can be used as a basis for further research and industrial applications.